LeetCode Best Time to Buy and Sell Stock

BabbleDay posted @ 2015年7月17日 15:14 in 刷题防身 with tags python leetcode , 959 阅读

系列一

def maxProfit(self, prices):
        rtn = 0
        if len(prices)!=0:
            buy = prices[0]
            for i in range( len(prices) ):
                buy = min(buy, prices[i])
                rtn = max(rtn, prices[i]-buy)
        return rtn

系列二:正常考虑单调

def maxProfit(self, prices):
        buy, sell, rtn = -1, -1, 0
        for i in range(len(prices)-1):
            if buy==-1 and prices[i+1]>prices[i]:
                buy = prices[i]
            if buy!=-1 and prices[i+1]<prices[i]:
                sell = prices[i]
                rtn += sell - buy
                buy = -1
        if buy!=-1:
            rtn += prices[-1] - buy
        return rtn

而实际上。。。若今天比昨天高,那就昨买今卖就好了= =

def maxProfit(self, prices):
        rtn = 0
        for i in range(1,len(prices)):
            if prices[i]>prices[i-1]:
               rtn += prices[i] - prices[i-1]
        return rtn
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